x^2+42x+432=0

Solution for x^2+42x+432=0 equation:

x^2+42x+432=0

a = 1; b = 42; c = +432;
Δ = b2-4ac
Δ = 422-4·1·432
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-6}{2*1}=\frac{-48}{2}
=-24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+6}{2*1}=\frac{-36}{2}
=-18
$